Question

1) log8 16
2) lg27+lg3 / lg15-lg5

Answer 1

1) log₈16 = x
$8^{x} = 16$
$2^{3x} = 2^{4}$
3x = 4
x = $frac{4}{3}$
2) $frac{lg27+lg3}{lg15-lg5} = frac{lg(27*3)}{lg( frac{15}{5}) } = frac{lg81}{lg3} = log_{3} 81=4$