Question

Решите таблицу! Прошу вас!

Answer 1

Ответ:

Объяснение:

(-5a+b)²=25a²-10ab+b²

(-5a-b)²=25a²+10ab+b²

(-5a)²-b²=(-5a-b)(-5a+b)

======================.

(3a+1/3 b)²=9a²+2ab+1/9 b²

(3a-1/3 b)²=9a²-2ab+1/9 b²

(3a)²-(1/3 b)²=(3a-1/3 b)(3a+1/3 b)

======================.

(5a²+0,2b²)²=25a^4+2a²b²+0,04b^4

(5a²-0,2b²)²=25a²-2a²b²+0,04b^4

(5a²)²-(0,2b²)²=(5a²-0,2b²)(5a²+0,2b²)

=====================================.

(a²b+(-4))²=(a²b-4)²=a^4b²-8a²b+16

(a²b-(-4))²=(a²b+4)²=a^4b²+8a²b+16

(a²b)²-(-4)²=(a²b-(-4))(a²b+(-4))=(a²b+4)(a²b-4)

==================.

(6+x²y²)²=36+12x²y^2+x^4y^4

(6-x²y²)²=36-12x²y²+x^4y^4

6²-(x²y²)²=(6-x²y²)(6+x²y²)