Question

(2-x)^2-4(3x-1)^2=0​

Answer 1

Ответ:

(2 – x)²– 4 • (3x + 1)²= 0

4 – 4x + x²– 4 • (9x²+ 6x + 1) = 0

4 – 4x + x²– 36x²– 24x – 4 = 0

– 28x – 35x²= 0

– 7x • (4 + 5x) = 0

x • (4 + 5x) = 0

x = 0

(4 + 5x) = 0

x = 0

x = – 4/5 = – 0,8