• Предмет: Математика
  • Автор: Аноним
  • Вопрос задан 2 года назад

помогите пожалуйста
решите пожалуйста​

Приложения:

Ответы

Ответ дал: ksyuwi
3

( 1 )

\frac{4}{7} +(-\frac{11}{14} )=\frac{8}{14}-\frac{11}{14}=-\frac{3}{14}   \\\\-\frac{4}{9}-\frac{5}{12}=-\frac{16}{36}-\frac{15}{36}=-\frac{31}{36}   \\\\-\frac{14}{25}*\frac{20}{21}=-\frac{14}{5}*\frac{4}{21}=-\frac{56}{105}\\\\\frac{14}{9}:(-\frac{16}{15})=\frac{14}{9}*(-\frac{15}{16})=\frac{7}{9}*(-\frac{15}{8})=-\frac{105}{72}=-1\frac{33}{72}

( 2 )

-\frac{8}{25}*\frac{15}{14}-\frac{11}{48}:(-\frac{7}{8})=-\frac{8}{25}*\frac{15}{14}-\frac{11}{48}*(-\frac{8}{7})=-\frac{4}{5}*\frac{3}{7}-\frac{11}{6}*(-\frac{1}{7})=\\\\=-\frac{12}{35}+\frac{11}{42}=-\frac{2}{35}+\frac{11}{7}=-\frac{2}{35}+\frac{55}{35}=\frac{53}{35}

( 3 )

-\frac{8}{19} *\frac{13}{15}-\frac{8}{19}*\frac{2}{15}=-\frac{104}{285}-\frac{16}{285}=-\frac{120}{285}=-\frac{24}{57}

\frac{24}{25}*\frac{37}{43}-\frac{24}{25}*(\frac{37}{43}- \frac{15}{16})=\frac{24}{25}*\frac{37}{43}-\frac{24}{25}*(\frac{592}{688} -\frac{645}{688})= \frac{24}{25}*\frac{37}{43}-\frac{24}{25}*(-\frac{53}{688})=\\\\=\frac{888}{1075}-\frac{6}{25}*(-\frac{53}{172} )=\frac{888}{1075}+\frac{318}{4300}=\frac{888}{1075}+\frac{159}{2150}=\frac{1776}{2150}+\frac{159}{2150}=\frac{1935}{2150}=\frac{287}{430}

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