Question

sin 2п/3+ cos 5п/6 подскажите решение

Answer 1

$\frac{ \sqrt{3} }{2} + ( - \frac{ \sqrt{3} }{2} ) = 0$

Answer 2

Ответ:

$sin\dfrac{2\pi}{3}+cos\dfrac{5\pi}{6}=sin(\pi -\dfrac{\pi}{3})+cos(\pi -\dfrac{\pi}{6})=sin\dfrac{\pi}{3}-cos\dfrac{\pi}{6}=\\\\\\=\dfrac{\sqrt3}{2}-\dfrac{\sqrt3}{2}=0$