Question

найдите целые решения системы неравенства
{14-4х>3(2-х)
{3,5+0,25(х+1)<2х​

Answer 1

Ответ:

Пошаговое объяснение:

$\displaystyle\bf\left \{ {{14-4x>3(2-x)} \atop {3.5+0.25(x+1)<2x}} \right. \ \ \ \left \{ {{14-4x>6-3x} \atop {3.5+0.25x+0.25<2x}} \right.\\\\\\\left \{ {{14-6>-3x+4x} \atop {3.75<2x-0.25x} \right.\ \ \ \left \{ {{x<8} \atop {1.75x>3.75}} \right. \ \ \ \left \{ {{x<8} \atop {x>3.75:1.75}} \right.\\\\\\\left \{ {{x<8} \atop {x>3\dfrac{3}{4}:1\dfrac{3}{4} }} \right. \ \ \ \left \{ {{x<8} \atop {x>\dfrac{15}{4}\cdot\dfrac{4}{7} }} \right.\ \ \ \left \{ {{x<8} \atop {x>2\dfrac{1}{7} }} \right.$

$\displaystyle\bf{x\in\Big(2\dfrac{1}{7} ;8\Big)}$

О т в е т: целые решения системы неравенств: 3; 4; 5; 6; 7