Question

(2в+в")"+в"(5-в)(5+в)-4в(в"-3)=
"- в квадрате

Answer 1

(2b+b²)²+b²(5-b)(5+b)-4b(b²-3)=4b²+4b³+b⁴+b²(25-b²)-4b³+12b=4b²+4b³+b⁴+25b²-b⁴-4b³+12b=4b²+25b²+12b=29b²+12b
Ответ: 29b²+12b