• Предмет: Математика
  • Автор: vladimzamyatin2017
  • Вопрос задан 2 года назад

очень срочно помогите решить, дам 20 баллов
плииииз ​

Приложения:

Ответы

Ответ дал: Miroslava227
2

Ответ:

1.

 {125}^{x} = 0 \\

нет корней

2.

 {( \frac{1}{4} )}^{x - 5}  =  \frac{1}{ \sqrt[8]{4} }  \\  {4}^{ - (x - 5)}  =  {4}^{ -  \frac{1}{8} }    \\   - x + 5  =  -  \frac{1}{8}  \\  - x =  -  \frac{41}{8}  \\ x =  \frac{41}{8}

3.

 {4}^{3x + 2}  =  {( \frac{1}{32} )}^{2x}  \\  {2}^{2(3x + 2)}  =  {2}^{ - 5 \times 2x}  \\ 6x + 4 =  - 10x \\ 16x =  - 4 \\ x =  - 0.25

4.

 {5}^{0.25x - 5}  = 625 \\  {5}^{0.25x - 5}  =  {5}^{4}  \\ 0.25x - 5 = 4 \\  \frac{x} {4}  = 9 \\ x = 36

5.

 {0.4}^{2x - 1}  = 0.16 \\  {0.4}^{2x - 1}  =  {(0.4)}^{2}  \\ 2x - 1 = 2 \\ 2x = 3 \\ x = 1.5

6.

 {17}^{x + 2.7}  =  \frac{1}{289}  \\  {17}^{x + 2.7}  =  {17}^{ - 2}  \\ x + 2.7 =  - 2 \\ x =  - 4.7

7.

 {0.09}^{2x - 9}  = 0.0081 \\  {0.09}^{2x - 9}  =  {0.09}^{2}  \\ 2x - 9 = 2 \\ 2x = 11 \\ x = 5.5

8.

 {( \frac{1}{25}) }^{2 - 16x}  - 1 = 0 \\  {( \frac{1}{25} )}^{2 - 16x}  =  {( \frac{1}{25}) }^{0}  \\ 2 - 16x = 0 \\ 16x = 2 \\ x =  \frac{1}{8}

9.

 {( \frac{1}{5} )}^{x - 4}  = 0.04 \\  {( \frac{1}{5}) }^{x - 4}  =  \frac{1}{25}  \\ x - 4 = 2 \\ x  = 6

10.

 {( \frac{2}{7}) }^{ 3x - 7 }  =  {3.5}^{x}  \\  {3.5}^{ - (3x - 7)}  =  {3.5}^{x}  \\  - 3x + 7 = x \\  - 4x =  - 7 \\ x =  \frac{7}{4}

11.

 {2.5}^{0.25x - 4}  =  {0.4}^{x - 121} \\  { (\frac{25}{10}) }^{0.25x - 4} =  (\frac{4}{10}   ) {}^{x - 121}  \\  {( \frac{5}{2}) }^{0.25x - 4}  =  (\frac{2}{5} ) {}^{x - 121}  \\ 0.25x - 4 =  - x + 121 \\ 1.25x = 125 \\ x = 100

12.

 {(3 \frac{6}{25}) }^{ {x}^{2} - x - 1 }  =  {( \frac{5}{9} )}^{2x - 16}  \\  {( \frac{81}{25}) }^{ {x}^{2} - x - 1 }  =  {( \frac{5}{9} )}^{2x - 16} \\  {( \frac{9}{5} )}^{2( {x}^{2}  - x - 1)}   =  {( \frac{5}{9} )}^{2x - 16}  \\ 2 {x}^{2}  - 2x - 2 =  - 2x + 16 \\ 2 {x}^{2}  = 18 \\  {x}^{2}  = 9 \\ x = \pm3


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