Question

решите систему неравенств :{2x + 1 < 5x - 11 3 (x + 2) _< 4x + 3​

Answer 1

$\left \{ {{2x+1<5x-11} \atop {3(x+2)\leq 4x+3}} \right.$

$\left \{ {{2x-5x<-1-11} \atop {3x+6\leq 4x+3}} \right.$

$\left \{ {{-3x<-12} \atop {3x-4x\leq -6+3}} \right.$

$\left \{ {{-3x<-12} \atop {-x\leq -3}} \right.$

$\left \{ {{-3x:(-3)>-12:(-3)} \atop {-x:(-1)\geq -3:(-1)}} \right.$

$\left \{ {{x>4} \atop {x>3}} \right.$

_______________________4//////////////////////////////////////       $x>4$

____________,3\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\    $x\geq 3$

Общее решение:     $x>4$

Ответ:  (4;    +∞)