Question

Хелпппппп! Помогите пжж

Answer 1

Ответ:

$\dfrac{8}{\sqrt2}=\dfrac{8\sqrt2}{\sqrt2\cdot \sqrt2}=\dfrac{8\sqrt2}{2}=4\sqrt2\\\\\\\dfrac{15}{\sqrt{11}-1}=\dfrac{15\cdot (\sqrt{11}+1)}{(\sqrt{11}-1)(\sqrt{11}+1)}=\dfrac{15\cdot (\sqrt{11}+1)}{11-1}=\dfrac{15\, (\sqrt{11}+1)}{10}=\dfrac{3\, (\sqrt{11}+1)}{2}\\\\\\\dfrac{14}{\sqrt{17}+\sqrt3}=\dfrac{14\, (\sqrt{17}-\sqrt3)}{(\sqrt{17}+3)(\sqrt{17}-\sqrt3)}=\dfrac{14\, (\sqrt{17}-\sqrt3)}{17-3}=\sqrt{17}-\sqrt3$