Question

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Answer 1

$\frac{99}{125}-(\frac{15}{125}+\frac{36}{125}+\frac{9}{125})=\frac{99}{125}-(\frac{15+36+9}{125})=\frac{99}{125}-(\frac{60}{125})=\frac{99}{125}-\frac{60}{125}=\frac{99-60}{125}=\frac{39}{125}$

$\frac{47}{99}+\frac{25}{99}-\frac{60}{99}=\frac{47+25-60}{99}=\frac{12}{99}=\frac{4}{33}$

$\frac{13}{50}-(\frac{22}{50} -\frac{19}{50} )=\frac{13}{50}-(\frac{22-19}{50})=\frac{13}{50}-(\frac{3}{50})=\frac{13}{50}-\frac{3}{50}=\frac{13-3}{50}=\frac{10}{50}=\frac{1}{5}$

$\frac{362}{700}+\frac{102}{700}-\frac{400}{700}=\frac{362+102-400}{700}=\frac{64}{700}=\frac{32}{350}=\frac{16}{175}$