Question

Решите уравнение:

(x+3)^2 - (x-2) (x+2) = 0​

Answer 1

$(x + 2) {}^{2} - (x - 2)(x + 2) = 0$

$x {}^{2} + 6x + 9 - (x - 2)(x + 2) = 0$

$x {}^{2} + 6x + 9 - (x {}^{2} - 4) = 0$

$x {}^{2} + 6 x + 9 - x {}^{2} + 4 = 0$

$6x + 9 + 4 = 0$

$6x + 13 = 0$

$6x = - 3$

$x = \frac{ - 13}{6}$

$x = - \frac{13}{6}$