Question

помогитееее пж срочно

Answer 1

$A(-3 \ ; \ 0)\\\\B(0 \ ; \ -2)\\\\\boxed{y=-\frac{2}{3}x-2}$

Answer 2

Объяснение:

$A(-3;0)\ \ \ \ \ B(0;-2)\\\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} \ \ \ \ \Rightarrow\\\frac{x-(-3)}{0-(-3)} =\frac{y-0}{-2-0}\\\frac{x+3}{3}=\frac{y}{-2}\ |*(-2)\\y=-2*(\frac{x}{3}+1)\\ y=-\frac{2}{3}x-2.$