Question

(a^2+4a)^2-a^2(a-2)(a+2)-4a^2(2a-1) при а=0,7 ​

Answer 1

(a^2+4a)^2-a^2(a-2)(a+2)-4a^2(2a-1) = (0.49+2.8)^2 - 0.49(0.49-4)  - 4*0.49*0.4 = 3.29^2 + 0.49*3.51 - 0.49*1.6 = 10.8241 + 0.49 * 1.91 = 10.8241 + 0.9359 = 11.76

Answer 2

(a² + 4a)² - a²(a - 2)(a + 2) - 4a² (2a - 1) = a⁴ + 8a³ + 16a² - a²(a² - 4) - 8a³ + 4a² =

= a⁴ + 20a² - a⁴ + 4a² =24a²

a = 0,7   ⇒   24a² = 24 * (0,7)² = 24 * 0,49 = 11,76

Ответ : 11,76