Question

Срочно!!!!!!!!!!!!!!!!!!!!

Answer 1

Ответ:

$y' = 4 \times 4 {x}^{3} - 3 \times ( - 3) {x}^{ - 4} + 5 \times \frac{4}{5} {x}^{ - \frac{1}{5} } + 0 = \\ = 16 {x}^{3} + \frac{9}{ {x}^{4} } + \frac{4}{ \sqrt[5]{x} } + 0$