Question

пж помогите на завтра нужно​

Answer 1

Ответ:

70.

$1)0.2 \sqrt{400} - \frac{1}{3} \sqrt{81} = 0.2 \times 20 - \frac{1}{3} \times 9 = 4 - 3 = 1$

$2) \sqrt{49} \times \sqrt{0.09} + \sqrt{2 {}^{3} + 1} = 7 \times \frac{3}{10} + 3 = 2.1 + 3 = 5.1$

$3)5 \sqrt{0.64} - \sqrt{5 {}^{2} + 12 {}^{2} } = 4 - 13 = - 9$

$4) \sqrt{5 \frac{4}{9} } - \sqrt{7 \frac{1}{9} } + 0.07 \sqrt{10000} = \frac{7}{3} - \frac{8}{3} + 7 = \frac{20}{3} = 6.6$

80.

$1) \sqrt{64 \times 36} = 8 \times 6 = 48 \\ 3) \sqrt{324 \times 0.25} = \sqrt{81} = 9 \\ 5) \sqrt{ \frac{25}{81} } = \frac{5}{9}$

88.

$1) \sqrt{72} = 6 \sqrt{2} \\ 2) \sqrt{80} = 4 \sqrt{5} \\ 3) \sqrt{300} = 10 \sqrt{3}$

$5) \frac{1}{2} \sqrt{48} = \frac{1}{2} \times 4 \sqrt{3} = 2 \sqrt{3}$

$8) \frac{2}{3} \sqrt{6 \frac{3}{4} } = \frac{1}{3} \times \sqrt{27} = \sqrt{3}$

94.

$1)(2 \sqrt{3} + 6 \sqrt{20} - 7 \sqrt{45} ) \sqrt{5} - \sqrt{60 } = 2 \sqrt{15} - 45 - 2 \sqrt{15} = - 45$

$2)(5 - 3 \sqrt{2} ) {}^{2} + (4 + 5 \sqrt{2} ) {}^{2} = 25 - 30 \sqrt{2} + 18 + 16 + 40 \sqrt{2} + 50 = 109 + 10 \sqrt{2}$