Question

Уравнение 7(6-2y)-10(1-y)= -2(y+1)+4(3y-5)

Answer 1

7(6-2y)-10(1-y)= -2(y+1)+4(3y-5).
42 - 14у - 10 + 10у = -2у - 2 + 12у - 20.
32 - 4у = 10у - 22
32 + 22 = 14у
14у = 54
у = $frac{54}{14} = frac{27}{4} = 6frac{3}{4}$

Answer 2

1.  42-14у-10+10у=-2у-2+12у-20
2.  -14у+10у-12у=-2-20+10-42
3.  -16у=-22+10-42
4.   у=-54/-16
5.   у=3.375