Question

f(x)=4x^4+2x^4-x^5 f’(1)-?

Answer 1

Ответ:

$f'(x) = 4 \times 4 {x}^{3} + 2 \times 4 {x}^{3} - 5 {x}^{4} = \\ = 16 {x}^{3} + 8 {x}^{3} - 5 {x}^{4} = 24 {x}^{3} - 5 {x}^{4}$

$f'(1) = 24 - 5 = 19$