Question

Срочно!!!!!!!!Вопрос жизни и смерти!!!

Answer 1

Ответ:

$f(x) = \frac{3}{ \sqrt{6 - 2x} } + \sqrt[3]{ {x}^{2} } - \frac{8}{ {x}^{8} } - 4 = \\ = 3 {(6 - 2x)}^{ - \frac{1}{2} } + {x}^{ \frac{2}{3} } - 8 {x}^{ - 8} - 4$

$f'(x) = 3 \times ( - \frac{1}{2} ) {(6 - 2x)}^{ - \frac{3}{2} } \times ( 6 - 2x)' + \frac{2}{3} {x}^{ - \frac{1}{3} } - 8 \times ( - 8) {x}^{ - 9} - 0 = \\ = - \frac{3}{2} \times \frac{1}{ \sqrt{ {(6 - 2x)}^{3} } } \times ( - 2) + \frac{2}{3 \sqrt[3]{x} } + \frac{64}{ {x}^{9} } = \\ = \frac{3}{ \sqrt{ {(6 - 2x)}^{3} } } + \frac{2}{3 \sqrt[3]{x} } + \frac{64}{ {x}^{9} }$