Question

Зробiть будьласка номер, 6,7,8,

Answer 1

Ответ:

6.

а)

$\frac{25 - x}{ \sqrt{x } + 5} = \frac{(5 - \sqrt{x})(5 + \sqrt{x} )}{5 + \sqrt{x} } = 5 - \sqrt{x}$

б)

$\frac{3 \sqrt{2} - 2}{5 \sqrt{2} } = \frac{ \sqrt{2}(3 - \sqrt{2} )}{5 \sqrt{2} } = \frac{3 - \sqrt{2} }{5}$

7.

а)

$\frac{46}{7 - \sqrt{3} } = \frac{46(7 + \sqrt{3} )}{(7 - \sqrt{3} )(7 + \sqrt{3} )} = \frac{46(7 + \sqrt{3} )}{49 - 3} = 7 + \sqrt{3}$

б)

$\frac{25}{ \sqrt{17} + \sqrt{2} } = \frac{25( \sqrt{17} - \sqrt{2} ) }{17 - 2} = \frac{5( \sqrt{17} - \sqrt{2} )}{3}$

8.

а)

$\sqrt{b {}^{11} } = \sqrt{b {}^{10} } \sqrt{b } = {b}^{5} \sqrt{b}$

б)

$\sqrt{5 {t}^{6} } = - t {}^{3} \sqrt{5}$