Question

помогите пожалуйста ​

Answer 1

Ответ:

формулы:

$\sin( \alpha ) = \pm\sqrt{1 - \cos {}^{2} ( \alpha ) } \\ \cos( \alpha ) = \pm \sqrt{1 - \sin {}^{2} ( \alpha ) } \\ 1 + {tg}^{2} \alpha = \frac{1}{ \cos {}^{2} ( \alpha ) } \\ tg \alpha = \pm \sqrt{ \frac{1}{ \cos {}^{2} ( \alpha ) } - 1 } \\ \cos( \alpha ) = \pm \sqrt{ \frac{1}{1 + {tg}^{2} \alpha } }$

1

$\sin( \alpha ) = \sqrt{1 - \frac{91}{100} } = \sqrt{ \frac{9}{100} } = \frac{3}{10} = 0.3$

2

$\sin( \alpha ) = \sqrt{1 - \frac{91}{100} } = \frac{3}{10} = 0.3$

3

$\sin( \alpha ) = \sqrt{1 - \frac{4 \times 6}{25} } = \sqrt{ \frac{1}{5} } = \frac{ \sqrt{5} }{5} \\ 5 \sin( \alpha ) = 5 \times \frac{ \sqrt{5} }{5} = \sqrt{5}$

4

$\sin( \alpha ) = \sqrt{1 - \frac{21}{25} } = \sqrt{ \frac{4}{25} } = \frac{2}{5}$

5

$\sin( \alpha ) = \sqrt{1 - \frac{9 \times 11}{100} } = \sqrt{ \frac{1}{100} } = \frac{1}{10} = 0.1$

6

$tg \alpha = \sqrt{ \frac{1}{ \frac{1}{2} } - 1} = \sqrt{2 - 1} = 1$

7

$tg \alpha = \sqrt{ \frac{1}{ \frac{25}{34} } - 1 } = \sqrt{ \frac{34}{25} - 1 } = \sqrt{ \frac{9}{25} } = \frac{3}{5 }$

8

$tg \alpha = \sqrt{ \frac{1}{ \frac{1}{10} } - 1 } = \sqrt{10 - 1} = \sqrt{9}$

9

$tg \alpha = \sqrt{ \frac{1}{ \frac{25}{ {26}^{2} } } - 1} = \sqrt{ \frac{ {26}^{2} }{25} - 1 } = \\ = \sqrt{ \frac{676 - 25}{25} } = \sqrt{ \frac{651}{25} } = \frac{ \sqrt{651} }{5}$

10

$tg \alpha = \sqrt{ \frac{1}{ \frac{1}{5} } - 1} = \sqrt{5 - 1} = \sqrt{4} = 2$

11

$\cos( \alpha ) = \sqrt{1 - \frac{8}{9} } = \sqrt{ \frac{1}{9} } = \frac{1}{3} \\ 3 \cos( \alpha ) = 3 \times \frac{1}{3} = 1$

12

$\cos( \alpha ) = \sqrt{1 - \frac{3}{4} } = \sqrt{ \frac{1}{4} } = \frac{1}{2}$

13

$\cos( \alpha ) = \sqrt{1 - \frac{91}{100} } = \frac{3}{10} = 0.3$

14

$\cos( \alpha ) = \sqrt{1 - \frac{51}{100} } = \sqrt{ \frac{49}{100} } = \frac{7}{10} = 0.7$