Question

решите уравнение СРОЧНО

Answer 1

$\frac{(2x-3)^{2} }{6}+\frac{x-4}{2} =-\frac{4}{3} \\\\\frac{(2x-3)^{2} }{6}*6+\frac{x-4}{2}*6 =-\frac{4}{3}*6\\\\(2x-3)^{2} +3(x-4)=-4*2\\\\4x^{2} -12x+9+3x-12+8=0\\\\4x^{2}-9x+5=0\\\\D=(-9)^{2}-4*4*5=81-80=1\\\\x_{1}=\frac{9-1}{8}=1\\\\x_{2}=\frac{9+1}{8}=1,25\\\\Otvet:\boxed{1 \ ; \ 1,25}$