Question

Помогите решить задачу.

Answer 1

Формула: $(aбb)^2=a^2б2ab+b^2$

№1

$(f-x)^2=f^2-2fx+x^2$

$(5x+y)^2=25x^2+10xy+y^2$

$(p-8)^2=p^2-16p+64$

$(a+4c)^2=a^2+8ac+16c^2$

$(5x-3y)^2=25x^2-30xy+9y^2$

$62^2=(60+2)^2=60^2+2\times 60 \times 2+2^2=3600+240+4=3844$

№2

$x^2-8x+16=(x-4)^2$

$4a^2+4ab+b^2=(2a+b)^2$

$\frac{1}{36} m^2-3mn+81n^2=(\frac{1}{6} m-9n)^2$

$0,25p^2+0,6pq+0,36q^2=(0,5p+0,6q)^2$