Question

Любое из 4 Помагите срочно ​

Answer 1

Ответ:

#1 f(x)= -2/3*x³+2x²-x

f'(x)=d/dx*(-2/3*x³+2x²-x)

f'(x)=d/dx(-2/3*x³)+d/dx*(2x²)-d/dx*(x)

f'(x)= -2/3*3x²+2*2x-d/dx*(x)

f'(x)= -2x²+4x-1

#2 g(x)=3cos(x)

g'(x)=d/dx*(3cos(x))

g'(x)=3*d/dx*(cos(x))

g'(x)=3*(-sin(x))

g'(x)= -3sin(x).