Question

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Answer 1

решение на фотографии)

Answer 2

Ответ:

$\\ ( \frac{1}{x {}^{2} + 4x + 4 } - \frac{3}{x {}^{2} + 2x } + \frac{2}{x {}^{2} } ) \div \frac{x {}^{2} + 2x - 8 }{ x {}^{3} - 4x} \\ \\ ( \frac{1}{(x + 2) {}^{2} } - \frac{3}{x \times (x + 2)} + \frac{2}{x {}^{2} } ) \times \frac{x {}^{3} - 4x }{ x {}^{2} + 2x - 8 } \\ \\ ( \frac{x - 3(x + 2)}{x(x + 2) { }^{2} } + \frac{2}{x {}^{2} }) \times \frac{x \times (x {}^{2} - 4 )}{x {}^{2} + 4x - 2x - 8} \\ \\ ( \frac{ - 2x - 6}{x(x + 2) {}^{2} } + \frac{2}{x {}^{2} } ) \times \frac{x \times (x - 2) \times (x + 2)}{(x + 4)(x - 2)} \\ \\ \frac{ - 2x {}^{2} - 6x + 2x {}^{2} + 8x + 8}{x \times (x + 2)} \times \frac{1}{x + 4} \\ \\ \frac{2x + 8}{x \times (x + 2)} \times \frac{1}{x + 4} \\ \\ \frac{2(x + 4)}{x \times (x + 2) } \times \frac{1}{x + 4} \\ \\ \frac{2}{x \times (x + 2)} \\ \\ \frac{2}{x {}^{2} + 2x}$