Question

Решите неравенства: (35 баллов!)

Answer 1

б) x² ≥ - 3

Ответ : x ∈ R , или   x ∈ (- ∞ ; + ∞)

$a)\frac{1}{3}\leq \frac{x}{6} +0,5\leq\frac{3}{4}\\\\\frac{1}{3}-0,5\leq \frac{x}{6} +0,5-0,5\leq\frac{3}{4}-0,5 \\\\-\frac{1}{6} \leq \frac{x}{6}\leq\frac{1}{4} \\\\-\frac{1}{6} *6\leq \frac{x}{6}*6\leq\frac{1}{4}*6\\\\-1\leq x\leq1,5\\\\Otvet:\boxed{x\in[-1 \ ; \ 1,5]}$