Question

Разложить на множители:
а)x-²81=x²-9²=(x-9)(x+9)
б)4y⁴-16x²=
B)8a³-27b⁶=
Г)125x⁹-8y⁶=

Answer 1

б)  $4y^4-16x^{2} =4(y^4-4x^{2} )=4(y^2-2x )(y^2+2x)$

в)  $8a^3-27b^6=(2a)^3-(3b^2)^3=(2a-3b^2)(4a^2+6ab^2+9b^4)$

г)  $125x^9-8y^6=(5x^3)^3-(2y^2)^3=(5x^{3}-2y^2 )(25x^{6}+10x^{3} y^{2}+4y^4 )$

Answer 2

Объяснение:

$1) {x}^{2} - 81 = {x}^{2} - {9}^{2} = (x - 9)(x + 9) \\ 2) {4y}^{4} - {16x}^{2} = 4( {y}^{4} - {4x}^{2} ) = 4( {y}^{2} - 2x)( {y}^{2} + x) \\ 3) {8a}^{3} - {27b}^{6} = {2}^{2} {a}^{3} - {3}^{3} {b}^{3 \times 2} = {(2a)}^{3} - ( {3b}^{2} )^{3} = (2a - {3b})^{2} ( {4a}^{2} + {6ab}^{2} + {9b}^{4} ) \\ 4)125 {x}^{9} - {8y}^{6} = {5}^{3} {x}^{3 \times 3} - {2}^{3} {y}^{3 \times 2} = {5}^{3} \times ( {x}^{3} ) ^{3} - {2}^{3} ( {y}^{2} )^{3} = ( {5x}^{3} )^{3} - ( {2y}^{2} )^{3} = ( {5x}^{3} - {2y}^{2} )( {25x}^{6} + {10x}^{3} {y}^{2} + {4y}^{4} ) \\ \\ tuburetka$