Question

Помогите пожалуйста, срочно нужно !!!

Answer 1

Ответ:

Пошаговое объяснение:

$\displaystyle \left \{ {{x-10<0} \atop {log_5x>1}} \right. \left \{ {{x<10\hfill} \atop {log_5x>log_55}} \right. \left \{ {{x<10} \atop {x>5}} \right. \Rightarrow 5<x<10$

$\displaystyle \left \{ {{log_{1/2}x<-2} \atop {x+1>3\hfill}} \right. \left \{ {{log_{\frac{1}{2} } x<log_{\frac{1}{2} }4\atop {x>2\hfill}} \right. \left \{ {{x>4} \atop {x>2}} \right. \Rightarrow x>4$

$\displaystyle \left \{ {{lnx>0} \atop {5-x<0}} \right. \left \{ {{lnx>ln1} \atop {-x<-5}} \right. \left \{ {{x>1} \atop {x>5}} \right. \Rightarrow x>5$

$\displaystyle \left \{ {{lgx<1} \atop {x+7>0}} \right. \left \{ {{lgx< lg10} \atop {x>-7\hfill}} \right. \left \{ {{x<10} \atop {x>-7}} \right. \Rightarrow -7<x<10$