Question

Помогите мне только 1 ненадо.

Answer 1

Ответ:

2)

$4 - (5x + 4) = 3x \\ 4 - 5x - 4 = 3x \\ - 5x - 3x = - 4 + 4 \\ - 8x = 0 \\ x = 0 \div - 8 \\ x = 0$

3)

$- (6x + 2) = 6(2 - x) \\ - 6x - 2 = 12 - 6x \\ - 2 = 12$

утверждение ложно для любого значения x

4)

$3 + (7x - 4) = 6 \\ 3 + 7x - 4 = 6 \\ 7x = 6 - 3 + 4 \\ 7x = 7 \\ x = 7 \div 7 \\ x = 1$

5)

$4(x - 2) - 3(3 + 2x) = 23 \\ 4x - 8 - 9 - 6x = 23 \\ 4x - 6x = 23 + 8 + 9 \\ - 2x = 40 \\ x = 40 \div - 2 \\ x = - 20$