Question

Вынесение общего множителя за скобки. Хелпаните,пожалуйста.

Answer 1

10. 2x^2y^3(x^3–4y)
11. 4mn^3(2m^2n–3m^4+5n^4)
12. (5–x)(2x–3)–(5–x)(x+5) далее (5–x)(2x–3–x–5)
13. a^2(a+4)(a–3(4+a))
^–значит возведение в степень

Answer 2

$10. \: \: \: \: 2x {}^{6} y {}^{3} - 8y {}^{4} x {}^{2} = 2x {}^{2} y {}^{3} (x {}^{4} - 4y) \\ 11. \: \: \: 8m {}^{3} n {}^{3} - 12m {}^{5} n {}^{3} + 20mn {}^{5} = 4mn {}^{3} (2m {}^{2} - 3m {}^{4} + 5n {}^{2} )$

$12. \: \: \: \: (5 - x)(2x - 3) + (x - 5)(x + 5) = 10x - 15 - 2x {}^{2} + 3x + x {}^{2} - 5 {}^{2} = - x {}^{2} + 7x - 40$

$13. \: \: \: \: a {}^{3} (a + 4) - 3a {}^{2} (4 + a) {}^{2} = a {}^{4} + 4a {}^{3} - 3a {}^{2} (16 + 8a + a {}^{2} ) = a {}^{4} + 4a {}^{3} - 48a {}^{2} - 24a {}^{3} - 3a {}^{4} = - 2a {}^{4} - 20a {}^{3} - 48a {}^{2} = - 2a {}^{2} (a {}^{2} + 10a + 24)$