Question

разложите на множители
$1) { 2x}^{2} - xy$
$2) {2y}^{4} + {6y}^{3} - {4y}^{2}$
$3)2a(a - 1) + 3(a - 1)$
$4)4x - 4y + ax - ay$
$5) {x}^{2} - 25$
$6) {ab}^{2} - {ac}^{2}$
$7) { - 3a}^{2} - 6ab { - 3b}^{2}$





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Answer 1

Ответ:

$1)2 {x}^{2} - xy = x(2x - y)$

$2)2 {y}^{4} + 6 {y}^{3} - 4 {y}^{2} = 2 {y}^{2} ( {y}^{2} + 3y - 2)$

$3)2a(a - 1) + 3(a - 1) = (a - 1)(2a + 3)$

$4)4x - 4y + ax - ay = 4(x - y) + a(x - y) = (x - y)(4 + a)$

$5) {x}^{2} - 25 = (x - 5)(x + 5)$

$6) {ab}^{2} - {ac}^{2} =a ( {b}^{2} - {c}^{2} ) = a(b - c)(b + c)$

$7) - 3 {a}^{2} - ab - 3 {b}^{2} = - 3( {a}^{2} + 2ab + {b}^{2} ) = - 3(a + b) {}^{2}$