Question

Распишите мне эти примеры.
-12с-0,5(6-5с)+4=
0,7(4-а)-0,2(3а+1)=
4/5(20t-5k)+1/4(16t-k)=​

Answer 1

Ответ:

$- 12c - 0.5(6 - 5c) + 4 = - 12c - 3 + 2.5c + 4 = - 95c + 1 \\ \\ 0.7(4 - a) - 0.2(3a + 1) = 2.8 - 0.7a - 0.6a - 0.2 = - 1.3a + 2.6 \\ \\ \frac{4}{5} (20t - 5k)+ \frac{1}{4} (16t - k) = 16t - 4k + 4t - \frac{1}{4} k = 20t - 4 \frac{1}{4} k$