Question

НУЖНО РЕШИТЬ ЦЕПОЧКУ!
Бензол (CH3Cl, AlCl3) → X1 (2Br2, hv) → X2 (изб. KOH(водн.)) → X3 ([Ag(NH3)2]OH) → X4 → C6H5COOH

Answer 1

Ответ:

C6H6+CH3Cl=C6H5CH3+HCl

C6H5CH3 +3Br2 = C6H5Br3 +3HBr

C6H5Br3 + KOH = C6H5OH+ KBr

C6H5OH + [Ag(NH3)2]OH] = C6H5COOH +Ag2+NH3 +H2O

Объяснение:

Answer 2

Ответ:

1) C6H6 + CH3Cl (AlCl3) = C6H5-CH3 (X1) + HCl;

2) C6H5-CH3 + 2Br2 (hv) = C6H5-CHBr2 (X2) + 2HBr;

3) C6H5-CHBr2 + 2KOH (вод. р-р) = C6H5-C(O)H (X3) + 2KBr + H2O;

4) C6H5-C(O)H + 2[Ag(NH3)2]OH = C6H5-COONH4 (X4) + 2Ag + 3NH3 + H2O;

5) C6H5-COONH4 + HCl = C6H5-COOH + NH4Cl.