Question

${x }^{2} + 3x = \frac{8}{ {x}^{2} + 3x - 2?}$
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Answer 1

x²+3x-2≠0, x≠(-3±√17)/2
пусть x²+3x-2= t, тогда
t+2= 8/t, t≠0
t²+2t-8=0
X= 4+32=36
t1= (-2-6)/2= -4
t2= (-2+6)/2= 2
1) x²+3x-2=-4
x²+3x+2=0
X= 9-8=1
x1= (-3-1)/2= -2
x2= (-3+1)/2= -1
2) x²+3x-2=2
x²+3x-4=0
X= 9+16= 25
x3= (-3-5)/2= -4
x4= (-3+5)/2= 1