Question

(x-8)(x+2)=0
(2k-1)(k-1)=0
(18+36z)(12-z)=0
y(6y+15)=0
(y-3)(y+2)=0
(3a-6)(4a+1)=0
(15+t)(15-30t)=0
n(5n+12)=0

решите пж​​

Answer 1

$1) x=8,-2$

$2) k= \frac{1}{2},1$

$3) z= \frac{1}{2} ,12$

$4) y=0,-\frac{5}{5}$

$5) y=3,-2$

$6) a=2, -\frac{1}{4}$

$7) t=-15,\frac{1}{2}$

$8) n=0,-\frac{12}{5}$