Question

6x^2-19+13
2x^2+7x-9?​

Answer 1

6х²-19+13=6х²-6=6(х²-1)=6(х-1)(х+1)

2х²+7х-9=2х²+9х-2х-9=х(2х+9)-(2х+9)=(2х+9)(х-1)