Question

Помогите пожалуста срочно нада.

Answer 1

Ответ:

$y = \sqrt{(5+x)(2x-2,4)} = \sqrt{10x-12+2x^{2} -2,4x}$

$y =\sqrt{2x^{2} +7,6x-12}$

$2x^2+7,6x-12\geq 0$

D = 7,6²-4·2·(-12) = 57,76+96 = 12,4²

$x_{1} = \frac{-7,6+\sqrt{153,76} }{2*2} = \frac{-7,6+12,4}{4} =\frac{4,8}{4} = 1,2$

$x_{2} = \frac{-7,6-\sqrt{153,76} }{2*2} = \frac{-7,6-12,4}{4} =\frac{-20}{4} = -5$

$y_{1} =\sqrt{2*1,2^{2} +7,6*1,2-12} = \sqrt{0} =0$

$y_{2} =\sqrt{2*(-5)^{2} +7,6*(-5)-12} = \sqrt{0} = 0$