Question

x2+x=(x+3)(3x-2)-2 (2 це квадрат​

Answer 1

x2+x=3x2-2x+9x-6-2
x2+x=3x2+7x-8
x2+x-3x2-7x+8=0
-2x2-6x+8=0
x2+3x-4=0
x2+4x-x-4=0
x•(x+4)-(x+4)=0
(x+4)•(x-1)=0

1) x+4=0, x=-4
2) x-1=0, x=1