Question

разрешите уравнение
$2 {x}^{2} - 8x = 0$
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Answer 1

Ответ:

2x²-8x=0

2x²-8x-0=0

a=2

b=-8

c=0

D = -8²-4·2·0 = 64-0 = 64

$x_{1} = \frac{8+\sqrt{64} }{2*2} = \frac{8+8}{4} = \frac{16}{4} = 4$

$x_{2} = \frac{8-\sqrt{64} }{2*2} = \frac{8-8}{4} = \frac{0}{4} = 0$.