Question

20балов алгебра помогите пожалуйста​

Answer 1

$1). \frac{x}{5} + \frac{y}{5} = \frac{x+y}{5} \\2). \frac{a}{4} +\frac{b}{4} = \frac{a+b}{4} \\3). \frac{a}{y} + \frac{2a}{y} =\frac{a+2a}{y} =\frac{3a}{y} \\4). \frac{5b^{2} }{3a} +\frac{13b^{2} }{3a} = \frac{5b^{2}+13b^{2}}{3a} = \frac{18b^{2}}{3a} = \frac{6b^{2}}{a}\\5). \frac{x+y}{19} +\frac{2x}{19} = \frac{x+y+2x}{19} =\frac{3x+y}{19} \\6). \frac{2c-x}{2b} +\frac{x}{2b} =\frac{2c-x+x}{2b} =\frac{2c}{2b} =\frac{c}{b} \\\\\\39.3$

$1). \frac{17-12x}{x} - \frac{10}{x} =\frac{17-12x-10}{x} =\frac{7-12x}{x} \\2). \frac{12p-1}{3p^{2} } -\frac{1+3p}{3p^{2}} =\frac{12p-1-(1+3p)}{3p^{2}} = \frac{12p-1-1-3p}{3p^{2}} =\frac{9p-2}{3p^{2}}$

$3). \frac{6y-3}{5y} -\frac{y+2}{5y} =\frac{6y-3-(y+2)}{5y} =\frac{6y-3-y-2}{5y}=\frac{5y-5}{5y} = \frac{5(y-1)}{5y}=\frac{y-1}{y}$