Question

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Answer 1

ответы на фотографии с решением

Answer 2

$\frac{24a {}^{7}b {}^{5} }{16a {}^{5} b {}^{3} } = \frac{3a {}^{2} b {}^{2} }{2}$

$\frac{3a + 3b}{a {}^{2} - b {}^{2} } = \frac{3(a + b)}{(a + b)(a - b)} = \frac{3}{a - b}$

$\frac{4a {}^{2} - 4ab + b {}^{2} }{4a {}^{2} - b {}^{2} } = \frac{(2a - b) {}^{2} }{(2a - b)(2a + b)} = \frac{2a - b}{2a + b}$

$\frac{2x {}^{2} - 2xy - x + y }{4x {}^{2} - 1} = \frac{(x - y)(2x - 1)}{(2x - 1)(2x + 1)} = \frac{x - y}{2x + 1}$

$\frac{125x {}^{3} - y {}^{3} }{25x {}^{2} - 10xy + y {}^{2} } = \frac{(5x - y)(25x {}^{2} + 5xy + y {}^{2} }{(5x - y) {}^{2} } = \frac{25x {}^{2} + 5xy + y {}^{2} }{5x - y}$