Question

Решите уравнение
(на фото)
пожалуйста

Answer 1

$\frac{\left(x+3\right)}{7}-\frac{\left(11-x\right)}{14}=\frac{\left(x+1\right)}{5}-\frac{\left(9-x\right)}{10}$

$\frac{3}{14}~x+\frac{-5}{14}=\frac{\left(x+1\right)}{5}-\frac{\left(9-x\right)}{10}$

$\frac{3}{14}~x+\frac{-5}{14}=\frac{3}{10}~x+\frac{-7}{10}$

$\frac{3}{14}~x+\frac{-5}{14}-\frac{3}{10}~x=\frac{3}{10}~x+\frac{-7}{10}-\frac{3}{10}~x$

$\frac{-3}{35}~x+\frac{-5}{14}=\frac{-7}{10}$

$\frac{-3}{35}~x+\frac{-5}{14}+\frac{5}{14}=\frac{-7}{10}+\frac{5}{14}$

$\frac{-3}{35}~x=\frac{-7}{10}+\frac{5}{14}$

$\frac{-3}{35}~x=\frac{-12}{35}$

$\frac{-3}{35}~x~\frac{35}{-3}=\frac{-12}{35}~\frac{35}{-3}$

$x=\frac{-12}{35}~\frac{35}{-3}$

$x=4$