Question

$\frac{x^{2} - 4 }{4x^{2} }$ * $\frac{2x}{x + 2 }$ при x = 4

Answer 1

$\frac{x^{2}-4 }{4x^{2} }*\frac{2x}{x+2}=\frac{(x+2)(x-2)*2x}{4x^{2} *(x+2)}=\frac{x-2}{2x} \\\\x=4 \\\\\frac{x-2}{2x}=\frac{4-2}{2*4} =\frac{2}{8}=\frac{1}{4}=\boxed{0,25}$