Question

Разкладить на множники пожалуйста ​

Answer 1

Ответ:

Пошаговое объяснение:

ax² + bx + c = a(x - x1)(x - x2)

a) x² - 6x + 8 = (x - 4)(x - 2)

D = 36 - 32 = 4

x1 = (6-2)/2 = 2

x2 = (6+2)/2 = 4

b) x² + 4x - 12 = (x - 2)(x + 6)

D = 16 + 48 = 64

x1 = (-4+8)/2 = 2

x2 = (-4-8)/2 = -6

c) 12x² -  7x + 1 = 12(x - 1/3)(x - 1/4) = (3x - 1)(4x - 1)

D = 49 - 48 = 1

x1 = (7-1)/24 = 1/4

x2 = (7+1)/24 = 1/3

d) 7x² - 8x + 1 = 7(x - 1/7)(x - 1) = (7x - 1)(x - 1)

D = 64 - 28 = 36

x1 = (8-6)/14 = 1/7

x2 = (8+6)/14 = 1

e) x² + 3x + 2 = (x + 1)(x + 2)

D = 9 - 8 = 1

x1 = (-3-1)/2 = -2

x2 = (-3+1)/2 = -1

f) x² - 2x - 3 = (x + 1)(x - 3)

D = 4 + 12 = 16

x1 = (2 - 4)/2 = -1

x2 = (2 + 4)/2 = 3