Question

Помогите решить срочно

Answer 1

sin²z = (1 - cos2z)/2 ⇒ √2·(√4sin²(3π/8) - 1) = √2·(2·0,5·(1 - cos(2·3π/8)) - 1) =

√2·(1 - cos(6π/8) - 1) = - √2·cos(3π/4) = - √2· (- √2/2) = 2/2 = 1