Question

помогите плиз прошуу ​

Answer 1

Пошаговое объяснение:

$(\frac{x}{x+1}+1 )*\frac{1+x}{2x-1}= \frac{x}{x+1}*\frac{1+x}{2x-1}+1*\frac{1+x}{2x-1}=\\ \\ =\frac{x}{2x-1}+ \frac{1+x}{2x-1}=\frac{2x+1}{2x-1}$

$\frac{5y^2}{1-y^2}:(1-\frac{1}{1-y} )= \frac{5y^2}{1-y^2}:(\frac{1-y-1}{1-y} )= \\ \\ \frac{5y^2}{1-y^2}:\frac{-y}{1-y}=\frac{5y^2}{1-y^2}*\frac{1-y}{-y}=-\frac{5y^2*(1-y)}{(1-y)(1+y)*y} =-\frac{5y}{1+y}$