Question

x + 3y = 12
4x + 2y = –18
помогите пожалуйста ​

Answer 1

x + 3y = 12

х+3у-12=12-12

х+3у-12=0

4x + 2y = –18

4х+2у+18=0

2х+у+9=0

Если это система.

{x + 3y = 12

4x + 2y = –18

{х=12-3у

4х+2у=-18

4(12-3у)+2у=-18

у=33/5

х=12-3×33/5

х=-39/5

(х, у)=-(39/5,33/5)

{-39/5+3×33/5=12

4×(-39/5+2×33/5=-18

{12=12

-18=-18

(х, у)=(-39/5,33/5)