Question

$log17( {3}^{x} + {2}^{y} ) = 1 \\ {3}^{x + 1} - 4 \times {2}^{y} = - 5$
помогиииите​

Answer 1

log(17) (3^x + 2^y) = 1

3^(x + 1) - 4*2^y = -5

====

3^x + 2^y  = 17       |*4

3*3^x  - 4*2^y = -5

и сложить

4*3^x + 4*2^y + 3*3^x  4*2^y = 68 - 5

7*3^x = 63

3^x = 9

3^x = 3^2

x = 2

3^2 + 2^y = 17

2^y = 8

2^y = 2^3

y = 3

ответ (2, 3)