Question

страница 195 номер 1425 Решите систему уравнений способом подстановки первое второепомогите пж​

Answer 1

Ответ:

Пошаговое объяснение:

$\left \{ {{x-y-2=0} \atop {2x-3y+1=0}} \right. \left \{ {{x=y+2 \atop {2x-3y+1=0}} \right. \left \{ {{x=y+2} \atop {2(y+2)-3y+1=0}} \right. \left \{ {{x=y+2} \atop {-y+5=0}} \right. \left \{ {{x=y+2} \atop {y=5}} \right. \left \{ {{x=5+2} \atop {y=5}} \right. \left \{ {{x=7} \atop {y=5}} \right.$

(7;5)

$\left \{ {{-x+y-4=0} \atop {4x+y+1=0}} \right. \left \{ {{y=x+4} \atop {4x+y+1=0}} \right. \left \{ {{y=x+4} \atop {4x+x+4+1=0} \right. \left \{ {{y=x+4} \atop {x=-1}} \right. \left \{ {{y=-1+4} \atop {x=-1}} \right. \left \{ {{y=3} \atop {x=-1}} \right.$

(-1;3)