Question

решите систему неравенств: ​

Answer 1

$\left \{ {{x^{2} - 4 > 0} \atop {x^{2} - 2x - 15 < 0}} \right. \\\\\left \{ {{|\sqrt{x^{2} > 2} |} \atop {x(x+3)-5(x+3) < 0}} \right. \\\\\left \{ {{|x| > 2} \atop {(x+3)*(x-5) < 0}} \right.$

Ответ:

x ∈ (-3, -2) ∪ (2, 5)